Answer:
Y=2x+2
Explanation:
The equation of a line with gradient "m" and passing through the point (x1, y1) can be found using the point-slope form of a line:
y - y1 = m (x - x1)
For a gradient of 2 and a point of (1, 4), we can substitute the values into the equation:
y - 4 = 2 (x - 1)
Expanding the right-hand side, we get:
y - 4 = 2x - 2
Adding 4 to both sides:
y = 2x + 2
So, the equation of the line with a gradient of 2 and passing through the point (1, 4) is y = 2x + 2.