Question

calculate the velocity at time 2.1 s for a ball thrown straight up with an initial velocity of 15.0 m/s. take the point of release to be y0

Answer 1

v = -5.38 m/s

Step-by-step explanation:

can be calculated using the kinematic equation for vertical motion under constant acceleration (gravitational acceleration):

v = v_0 + a * t

v = 15.0 m/s + (-9.8 m/s^2) * 2.1 s

= 15.0 m/s - 20.38 m/s

= -5.38 m/s