Question

can anyone help me with this problem it is 3x-y=2 and y= 1/3x-11 and I have to answer if its in parallel, perpendicular or neither

Answer 1

To determine if the lines represented by the equations 3x - y = 2 and y = 1/3x - 11 are parallel, perpendicular, or neither, you need to find the slopes of both lines and compare them.

The slope of the first line, 3x - y = 2, can be found by rearranging the equation into slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept. Solving for y:

y = -3x + 2

So the slope of the first line is -3.

The slope of the second line, y = 1/3x - 11, is simply 1/3.

Parallel lines have the same slope. Perpendicular lines have negative reciprocal slopes.

Since the slopes of the lines are not equal, they are not parallel. And since the product of their slopes is not -1, they are not perpendicular. Hence, they are neither parallel nor perpendicular

Answer 2

neither

Explanation:

3x - y = 2 put this is slope-intercept form

-y = -3x + 2

y = 3x - 2 compare this to the other equation y = 1/3x - 11

slope of the 1st one: m = 3

slope of the 2nd one: m = 1/3

if the lines were parallel, the slopes would be the same

if the lines were perpendicular, one slope would be the negative reciprocal of the other