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What are the roots of 2x^4-26x^2-28

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Answer: To find the roots of a polynomial equation, we can use various methods, such as factoring, synthetic division, or the quadratic formula. One common method to find the roots of a quartic polynomial (degree 4) is to use the factor theorem, which states that if a polynomial equation has a root "r", then "r" is a factor of the polynomial.

In this case, we can factor 2x^4-26x^2-28 as:

2x^4 - 26x^2 - 28 = 2(x^2 - 7)(x^2 + 4)

So, the roots of 2x^4-26x^2-28 are x = ±√7 and x = ±i√2.

These are the solutions to the equation 2x^4-26x^2-28 = 0.

Explanation:

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