99.2k views
1 vote
What are the roots of 2x^4-26x^2-28

1 Answer

2 votes

Answer: To find the roots of a polynomial equation, we can use various methods, such as factoring, synthetic division, or the quadratic formula. One common method to find the roots of a quartic polynomial (degree 4) is to use the factor theorem, which states that if a polynomial equation has a root "r", then "r" is a factor of the polynomial.

In this case, we can factor 2x^4-26x^2-28 as:

2x^4 - 26x^2 - 28 = 2(x^2 - 7)(x^2 + 4)

So, the roots of 2x^4-26x^2-28 are x = ±√7 and x = ±i√2.

These are the solutions to the equation 2x^4-26x^2-28 = 0.

Explanation:

User Puneet Sinha
by
7.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories