Check the picture below.
so hmmm let's firstly convert the angles to degrees only.
so there are 60 minutes in 1 degree, so 10' is really 10/60 = 1/6 of a degree, so 112°10' is really just 112 and 1/6 degrees.
15°20' is just well, 20/60 = 1/3, so that converted to degrees only will be 15 and 1/3 degrees.
now, a triangle has a total of 180° interior angles, so let's get the angle A
![\stackrel{mixed}{112(1)/(6)}\implies \cfrac{112\cdot 6+1}{6}\implies \stackrel{improper}{\cfrac{673}{6}} ~\hfill \stackrel{mixed}{15(1)/(3)} \implies \cfrac{15\cdot 3+1}{3} \implies \stackrel{improper}{\cfrac{46}{3}} \\\\[-0.35em] ~\dotfill\\\\ 180-\cfrac{673}{6}-\cfrac{46}{3}\implies \cfrac{105}{2}\implies 52.5^o\impliedby \measuredangle A \\\\[-0.35em] \rule{34em}{0.25pt}](https://img.qammunity.org/2024/formulas/mathematics/college/fsqdiph82bcd101rj1r0evqlyy3si1kvwd.png)
![\textit{Law of sines} \\\\ \cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{\sin(C)}{c}=\cfrac{\sin(A)}{a}\implies \cfrac{\sin((46)/(3)^o)}{c}=\cfrac{\sin(52.5^o)}{354}\implies \cfrac{\sin((46)/(3)^o)}{\sin(52.5^o)}=\cfrac{c}{354} \\\\\\ \cfrac{354\sin((46)/(3)^o)}{\sin(52.5^o)}=c\implies 117.99^o\approx c=AB](https://img.qammunity.org/2024/formulas/mathematics/college/7sorzgn8lg7kx2oiou8lbaa063zki3xu33.png)
Make sure your calculator is in Degree mode.