Answer:
The answer is 6 moles.
Step-by-step explanation:
To calculate the amount of Al2S3 that can be produced from 12 moles of Al, we need to determine the amount of S that is required:
12 moles Al / 2 moles Al per mole Al2S3 = 6 moles Al2S3
3 moles S per mole Al2S3 * 6 moles Al2S3 = 18 moles S
Since 12 moles of Al are available, the maximum amount of Al2S3 that can be produced is 6 moles.