9 courses for 4 credits.
Use a system of equations. Let’s say that the number of courses worth 3 credits is X and the number of courses worth 4 credits is Y.
The total number of courses the student took was 15, so X+Y=15.
Each X course was worth 3 credits each and each Y course was worth 4 credits each, for a total of 54, so 3X+4Y=54.
I’m going to take the first equation and solve it for X so I can plug it in to the second equation.
X=15-Y.
Now, plug it in to the second equation to solve for Y.
3(15-Y)+4Y=54
1. Distribute what’s inside the parenthesis.
45-3Y+4Y=54
2. Combine like terms.
45+Y=54
3. Subtract 45 from both sides.
Y=9