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Write an equation for a parabola that has a vertex at (2, 3), focus at (2,5), and directrix at y = 1. f(x) = (x - 2)² +3 f(x) = 2(x - 5)² + 2 f(x)=(x-3)² + 2 f(x) = 2(x - 3)² + 1
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Mar 27, 2024
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Write an equation for a parabola that has a vertex at (2, 3), focus at (2,5), and directrix at y = 1.
f(x) = (x - 2)² +3
f(x) = 2(x - 5)² + 2
f(x)=(x-3)² + 2
f(x) = 2(x - 3)² + 1
Mathematics
high-school
Alif Jahan
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Alif Jahan
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Your answer is: f(x)= 2(x-3)^2 +1
y moves the parabola up and down on the x-axis, if y=1 then it would move up one
Sayan Sen
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Apr 1, 2024
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Sayan Sen
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