Answer: pls braiinliest :D
To find the equation of the line passing through the point (8, -2) that is perpendicular to the line y = 4/5x + 4, we can use the concept of the slope of a line. The slope of a line perpendicular to another line has a negative reciprocal slope.
The slope of the line y = 4/5x + 4 is 4/5. The negative reciprocal of 4/5 is -5/4.
So, the slope of the line passing through (8, -2) and perpendicular to y = 4/5x + 4 is -5/4.
Next, we can use the point-slope form of a line to find the equation of the line:
y - y1 = m(x - x1), where m is the slope and (x1, y1) is the given point.
Substituting the values, we get:
y - (-2) = -5/4 (x - 8)
Expanding and solving for y, we get:
y = -5/4x + 26/2
y = -5/4x + 13
The equation of the line passing through the point (8, -2) that is perpendicular to the line y = 4/5x + 4 is y = -5/4x + 13.
Explanation: