To find an equation for the line that is parallel to g(x) = -1x - 5 and passes through the point (10,1), we need to use the slope-point form of a line.
First, let's find the slope of g(x) = -1x - 5, which is -1. Then, we can use the slope and the point (10, 1) to write the equation of the line in slope-point form:
y - 1 = -1 (x - 10)
Rearranging the equation, we can write it in the point-intercept form:
y = -1x + (1 + 10) = -1x + 11
So, the equation of the line parallel to g(x) = -1x - 5 passing through the point (10,1) is y = -1x + 11 in point-intercept form.