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How do you solve this?

(3^{x-1}*27^x*9^2)/(3^{2x-4)*81^x}

User Mbpro
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1 Answer

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Answer: The expression can be simplified as follows:

(3^{x-1} * 27^x * 9^2) = 3^{x-1 + 2} * 27^x

(3^{2x-4) * 81^x} = 3^{2x-4 + 2x} * 3^{-2x}

Replace in the expression: (3^{x-1 + 2} * 27^x) / (3^{2x-4 + 2x} * 3^{-2x}) = 3^{x-1 + 2 - 2x + 4} * 27^x / 3^4 = 3^3 * 27^x / 81

So the simplified expression is 3^3 * 27^x / 81.

Explanation:

User Peter F
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