Question

Assuming independent assortment, what phenotypic ratio would you expect to see if an individual with the genotype RrGg is self crossed? Assume that R is dominant over r and G is dominant over g.

Answer 1

For a self-crossed individual with genotype RrGg assuming independent assortment, the expected phenotypic ratio would result in a 9:3:3:1 distribution, representing combinations of dominant and recessive traits expressed in the offspring.

Step-by-step explanation:

When an individual with the genotype RrGg is self-crossed, assuming independent assortment, you would expect to see a phenotypic ratio of 9:3:3:1. The individual produces four types of gametes in equal proportions: RG, Rg, rG, and rg. Using a Punnett square to diagram the cross between these gametes, you will see 16 possible offspring combinations. The phenotypic ratio comes from the expression of dominant and recessive traits, where R represents the dominant allele for one trait and G for another, while r and g are their respective recessive alleles. Therefore, the expected phenotypic ratio would be 9 expressing both dominant traits (RG), 3 expressing the first dominant and second recessive trait (Rg), 3 expressing the first recessive and second dominant trait (rG), and 1 expressing both recessive traits (rg).