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Solve 9=2x^2+3x in quadratic equation

User Brezhnews
by
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1 Answer

1 vote

Answer: x=-3 & x=3/2

Step-by-step explanation:

1. Simplify the expression

- Divide both sides by the same factor

9=2x^2+3x

2x^2 + 3x - 9 = 0

2. Use the quadratic formula

- Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

2x^2 + 3x - 9 = 0

a = 2

b = 3

c = -9

x = √-3±3^2−4⋅2(−9)/2⋅2

3. Simplify, again.

- Evaluate the exponent

- Multiply the numbers

- Add the numbers

- Evaluate the square root

x=−3±9/4

4. Separate the equations

- To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.

x=−3+9/4

x=-3-9/4

5. Solve

- Rearrange and isolate the variable to find each solution.

x=3/2

x=-3

User Rcarvalho
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7.5k points