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For the Haber process, N₂ + 3H₂-2NH3, what theoretical volume of ammonia (NH3

hould be produced if we start with 5.0L of N₂ if STP?

29.9
10.0
22.4
44.8

User Gombat
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1 Answer

4 votes

Step-by-step explanation:

The theoretical volume of ammonia that should be produced in the Haber process if we start with 5.0 L of nitrogen (N2) at standard temperature and pressure (STP) can be calculated as follows:

1 mole of N2 reacts with 3 moles of H2 to form 2 moles of NH3

Thus, the number of moles of N2 present can be calculated using the Ideal Gas Law:

PV = nRT

Where n is the number of moles of gas, R is the gas constant, T is the temperature in Kelvin, P is the pressure in atmospheres, and V is the volume in liters.

At STP (0°C and 1 atm), the volume of one mole of gas is 24.45 L.

Given 5.0 L of N2 at STP, the number of moles of N2 can be calculated as:

n = (PV)/RT = (1 atm)(5.0 L)/(0.0821 atmL/molK)(273 K) = 1.96 moles

The number of moles of NH3 produced can then be calculated as:

n = (2 moles of NH3)/(1 mole of N2) = 2 moles/1 mole = 2 moles

The volume of NH3 can be calculated as:

V = nRT/P = (2 moles)(0.0821 atmL/molK)(273 K)/(1 atm) = 44.8 L

So, the theoretical volume of ammonia (NH3) that should be produced if we start with 5.0 L of N2 at STP is 44.8 L.

User Yibo Long
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