To find the probability that the player misses three consecutive free throws, we need to calculate the probability of missing a single shot (1 - 93%) and raise it to the power of 3, since the shots are independent:
1 - 0.93 = 0.07
0.07^3 = 0.00343
So, the probability that the player misses three consecutive free throws is approximately 0.00343, or 0.343%.