Work Shown:
xy + 2x + 3x^2 = 4
d/dx[ xy + 2x + 3x^2 ] = d/dx[4]
d/dx[ xy ] + d/dx[ 2x ] + d/dx[ 3x^2 ] = d/dx[4]
y + xy' + 2 + 6x = 0
xy' = -6x-y-2
y' = (-6x-y-2)/x
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