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A rectangular garden has a length of 57 m and a width of 42 m. How many m2 will decrease the area of a garden, if the ornamental fence with a width of 60 cm will be planted inside its perimeter?

User Tei
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2 Answers

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Answer:

The width of the ornamental fence is 60 cm, which is equal to 60/100 = 0.6 meters.

The total length of the ornamental fence that will be planted inside the perimeter of the rectangular garden is 2 * (57 m + 42 m) = 2 * 99 m = 198 m.

The decrease in the area of the garden due to the ornamental fence is 0.6 m * 198 m = 118.8 m^2.

User CeePlusPlus
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The area of the rectangular garden can be calculated as follows: 57 m * 42 m = 2406 m^2.

The ornamental fence with a width of 60 cm has a width of 0.6 m. If the fence is planted inside the perimeter of the garden, the length of the garden will decrease by 2 * 0.6 m = 1.2 m and the width of the garden will decrease by 2 * 0.6 m = 1.2 m.

So, the new length and width of the garden will be 57 m - 1.2 m = 55.8 m and 42 m - 1.2 m = 40.8 m, respectively.

The new area of the garden can be calculated as follows: 55.8 m * 40.8 m = 2270.784 m^2.

Finally, the decrease in area can be calculated as follows: 2406 m^2 - 2270.784 m^2 = 35.216 m^2.

Therefore, the area of the garden will decrease by 35.216 m^2.

User Hassan Boutougha
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