Explanation:
Given eqn
y=1/3x+4
1/3x-y+4=0
eqn of line perpendicular to the given eqn.,
x+1/3y+k=0
since the reqd. line contains the point (2,-3)
2+1/3 (-3)+k=0
2-1+k=0
k=-1
so
x+1/3y-1=0
1/3y=1-x (in slope intercept form)
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