Question

In Young's double-slit interference experiment, if the with bright fringe for light.

of wavelength 2, 0, 1, 2,-) coincides with the with dark fringe

of wavelength 2, (m=1,2,3.), then the ratio ¿/2, is (d) 2+1

Answer 1

The relationship between the wavelengths and the position of the fringes in Young's double-slit interference experiment is determined by the equation: d(sinθ1 - sinθ2) = mλ, where d is the distance between the slits, λ is the wavelength of the light, and m is the order of the fringe (m=0 for the central bright fringe, m=±1 for the first set of bright fringes, etc.). Therefore, if the bright fringe for wavelength 2 coincides with the dark fringe for wavelength 2, then the ratio d/λ is equal to (m+1)/2.