Answer:
x = 11 , TB = 12 cm
Explanation:
given a tangent and a secant from an external point to the circle, then
the square of the measure of the tangent is equal to the product of the measures of the secant's external part and the entire secant, that is
TC × TB = TA²
3(3 + x - 2) = 6²
3(x + 1) = 36 ( divide both sides by 3 )
x + 1 = 12 ( subtract 1 from both sides )
x = 11
then
TB = TC + CB = 3 + (11 - 2) = 3 + 9 = 12 cm