Question

The arm of a crane at a construction site is 16.0 m long and it makes an angle of 11.3 with the horizontal assume that the maximum load the crane can handle is limited by the amount of torque the load produces around the base of the arm what maximum torque in the Crane withstand is the maximum load the crank handle is 468 N

Answer 1

76.5

Step-by-step explanation:

To find the maximum torque the crane can withstand, we can use the formula: torque = force x distance x sin(angle).

Given that the arm of the crane is 16.0 m long and makes an angle of 11.3 degrees with the horizontal, we can substitute these values into the formula:

torque = force x distance x sin(angle)

Since the maximum load the crane can handle is 468 N, we can substitute that value for force:

torque = 468 N x 16.0 m x sin(11.3 degrees)

The unit of torque is Newton-meters (N*m). To get the torque, you need to convert the angle to radians by multiplying the degree by pi/180.

torque = 468 N x 16.0 m x sin(11.3 x pi/180)

You will get the maximum torque the crane can withstand is about 76.5 N*m.