Answer:
Explanation:
fog)oh(x) = fo(goh)x. 3) If f(x) and g(x) are one-one functions, then gof(x) is also one-one function. 4) If f(x) and g(x) are on-to functions, then gof(x) is also on-to function. 5) If f(x) and g(x) are bijective functions, then gof(x) is also a bijective function.