Question

There are five consecutive odd integers. The sum of the three least integers is 3 more than the sum of the two greatest. Find the integers

Answer 1

7, 8, 9, 10 and 11

Explanation:

Let:

a = smallest integer

Then the five consecutive integers in ascending order will be:

a, (a + 1), (a + 2), (a + 3), (a + 4)

According to the statement in the question:

a + (a + 1) + (a + 2) = (a + 3) + (a + 4) + 3

3a + 3 = 2a + 10

a = 7

Answer 2

11, 13, 15, 17, 19

Explanation:

The numbers: (x)+(x+2)+(x+4)+(x+6)+(x+8)

Given: (x)+(x+2)+(x+4) = 3+(x+6)+(x+8) => 3x + 6 = 2x + 17 => x = 11

The integers: 11, 13, 15, 17, 19