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At the dog park, there are several dogs with their owners. Counting heads, there are 20; counting legs, there are 62. How many dogs and owners are there?

1 Answer

5 votes
Suppose we let x represent the number of dogs and y be the number of owners at the dog park. We know that a dog has four legs while a human being has two, considering that both are on normal conditions. Since both of them only have one head, we can form a system of linear equations similar to

x
+
y
=
20
4
x
+
2
y
=
62

(Eq. 1)
(Eq. 2)



We can simplify equation 2 by dividing both sides of the equation by 2. Thus, we have

2
x
+
y
=
31

(Eq. 2)



We can subtract the simplified form of equation 2 from equation 1. Subtracting allows us to eliminate the variable y. Doing so, the resulting equation is


x
=

11

Therefore, we have
x
=
11
. Using equation 1 to solve for y, we have

x
+
y
=
20
y
=
20

x
y
=
20

11
y
=
9


Therefore, there are 11 dogs and 9 humans at the dog park.

User Nulano
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