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What is the value of θ for the first diffraction line (n = 1) in bcc iron (atomic radius 126 pm) when the X-ray wavelength is 58.0 pm? Hint: Consider the closest set of lattice planes.

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Final answer:

The value of θ for the first diffraction line in bcc iron when the X-ray wavelength is given can be found using the Bragg's Law equation. Plugging in the values and solving the equation gives a value of θ ≈ 60.43°.

Step-by-step explanation:

The Bragg's Law equation is used to solve this type of problem. The equation is given by:

nλ = 2dsin(θ)

Where:

  • n = order of diffraction (in this case, n = 1)
  • λ = wavelength of the X-ray (58.0 pm = 0.0580 nm)
  • d = spacing between the closest set of lattice planes
  • θ = angle of diffraction (we need to find this)

Plugging in the values, we have:

1 * (0.0580 nm) = 2d * sin(θ)

We can rearrange the equation to solve for θ:

θ = arcsin[(1 * (0.0580 nm)) / (2d)]

The formula for the atomic radius of the bcc lattice is:

d = (4/√3) * r

Plugging in the values, we have:

d = (4/√3) * 126 pm = 290.07 pm = 0.0290 nm

Finally, we can substitute the value of d into the equation for θ:

θ = arcsin[(1 * (0.0580 nm)) / (2 * 0.0290 nm)]

Solving this equation gives:

θ ≈ 60.43°

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