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Find all real zeros of the function y=3x+1 a. 1/3 b.-1/3 c. 3, 1 d. 3

User Kirth
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1 Answer

3 votes

Answer:

The zeroes of the function are:
(-1)/(3).

Option b would be the correct answer.

Explanation:

The zeros of a function are defined as the point at which the value of the function is zero. We can say the zeros are the x values where the graph intersects the x-axis. We obtain these algebraically by setting the function equal to zero then solving.

Given


y=3x+1

Lets find all real zeros of the function.

Replace
y with 0.


0=3x+1

Subtract 1 from both sides of the equation


-1=3x

Divide both sides of the equation by 3.


(-1)/(3) =(3x)/(3)

Simplify the right side by cancelling the common factor of 3.


(-1)/(3) =x

User Sandeep Kumar P K
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