Question

7. A 50 kg bicyclist on a 10 kg bicycle speeds up from 5.0 m/s to 10 m/s.

Given:
(a) What was the total kinetic energy before accelerating?
(b) What was the total kinetic energy after accelerating?
(c) How much work was done to increase the kinetic energy of the bicyclist? (Hint : Work = Δ KE = KEf - KEi)

Answer 1

a)-750J ; b)-3000J ; c)-2

Step-by-step explanation:

a)- (K.E.1)=mu²/2=60×25/2=750J

b)-(K.E.2)=mv²/2=60×100/2=3000J

c)-Work done= (K.E.2)-(K.E.1)=2250J