The complete model for
would then show
with a remainder of 1, giving us a quotient of 16 with a remainder of 1. The equation is:
![\[ 49 / 3 = 16 \, \text{R} \, 1 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/67mqwznd55nmb9m6wfwib4rfzgssf3vkk5.png)
The image appears to show a division model for the problem
.
To find the quotient of
, you divide 49 by 3. The division model shows part of the process:
1.
, which has been taken from the 49. This leaves a remainder to be divided.
2. To find out the remaining number, we subtract 18 from 49:
.
3. We then see how many times 3 can go into the remaining 31 without going over.
Let's calculate that.
After subtracting the initial 18 (which is
), we have 31 left. The number 3 goes into 31 a total of 10 times with a remainder of 1.
Therefore, in the division model:
- The first box (next to the number 6) would be 10, indicating that 3 goes into the remaining 31 ten times.
- The second box, which represents the remainder, would be 1.
The complete model for
would then show
with a remainder of 1, giving us a quotient of 16 with a remainder of 1. The equation is:
![\[ 49 / 3 = 16 \, \text{R} \, 1 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/67mqwznd55nmb9m6wfwib4rfzgssf3vkk5.png)