Question

The energy given off as heat by 500 g of an alloy as it cools by 25°C raises the

temperature of 250 g of water from 20°C to 28°C. Calculate the specific heat
of the alloy (in J/kg K). Remember that the specific heat of water is 4180 J/kg-K.
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Answer 1

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Step-by-step explanation:

The heat the water gains is the heat lost by the metal ...

Hw = .25 kg * (28- 20 C) * 4180 J/(kg K) = 8360 J

So the metal gains 8360 J and cools by 25 °C

500g = .5 kg

8360 /(.5kg* 25 C) = 668.8 J /(kg K)

Note: Remember that a degree C = one K)