Question

Washington, DC is on Eastern standard time, Minneapolis is on Central standard time (1 hr earlier than Eastern standard time), and Las Vegas is on Pacific standard time (3 hrs earlier than Eastern standard time).

A flight leaves Washington, DC at 9:45 A.M. Eastern standard time, stops for 2 hours and 20 minutes in Minneapolis, then arrives in Las Vegas at 4:30 P.M. Pacific standard time.

How long is the plane actually flying?

Answer 1

The plane's actual flying time from Washington, D.C. to Las Vegas, when accounting for time zone differences and layover, is 7 hours and 25 minutes.

Step-by-step explanation:

To calculate the actual flying time, we will consider the differences in time zones between Washington, DC, Minneapolis, and Las Vegas, as well as the layover time in Minneapolis.

Step-by-step Calculation:

Flight departure from Washington, DC at 9:45 A.M. EST.

Arrival in Minneapolis, which is one hour behind EST, so the local time of arrival would be 9:45 A.M. CST (if flight duration was instant).

With a 2-hour 20-minute layover, the plane would leave Minneapolis at 12:05 P.M. CST.

Las Vegas is three hours behind EST, meaning the destination time zone is PST.

Flight arrives in Las Vegas at 4:30 P.M. PST. Translating this to EST for comparison, we add three hours, resulting in 7:30 P.M. EST.

Subtract the departure time in EST from the arrival time in EST to find the elapsed time: 7:30 P.M. – 9:45 A.M. = 9 hours and 45 minutes.

Subtract the layover duration from the total elapsed time: 9 hours 45 minutes – 2 hours 20 minutes = 7 hours and 25 minutes of actual flight time.

Answer 2

Step-by-step explanation:

When the plane landed in Las Vegas it was 4:30PM Pacific time - this converts to 730 PM Eastern time.

The entire trip lasted from 9:45 am to 7:30 pm. This is a total of 9 hours and 45 minutes.

Subtract 2 hours and 20 minutes for the layover and the plane was flying

for 7 hours and 25 minutes.

9 - 2 = 7 hours and 45 minutes - 20 = 25 minutes