Question

Please help!!

See picture for details!

sin(A) =
cos(A) =
tan(A)=
sec(A)
csc(A) =
cot(A) =

Answer 1

Explanation:

In the diagram there are two vertex A & B

Let us assume the 3rd vertex to be C

AB is the hypotenuse which is 8

AC is the adjacent side which is 6

CB is the opposite side. Let us assume it to be x for now

`hypotenuse^(2) = opposite^(2) +adjacent^(2)`

`8^(2) =x^(2)+6^(2) \\64=x^(2) +36\\x^(2) =64-36=28\\x=2 √(7)`

sinA=CB/AB = 2
`\sqrt{7` /8

CosA=AC/AB=6/8

TanA=sinA/CosA=CB/AC=2
`√(7)`/6

Similarly,

CosecA=1/SinA

SecA=1/CosA

CotA=1/TanA