Answer:
The balanced chemical equation for the reaction is: 2 Al(OH)3 + 3 H2SO4 -> Al2(SO4)3 + 6 H2O
From the balanced equation, we can see that for every 2 moles of Al(OH)3 and 3 moles of H2SO4 that are consumed, 1 mole of Al2(SO4)3 and 6 moles of H2O are produced. Therefore, the ratio of moles of Al2(SO4)3 to moles of H2O is 1:6.
Given that 6.0 moles of Al2(SO4)3 are produced, we can use the ratio of moles to find the number of moles of H2 that are also produced:
6.0 moles Al2(SO4)3 / 1:6 ratio = 1.0 moles H2
Therefore, 1.0 moles of H2 will also be produced in this reaction if 6.0 moles of Al2(SO4)3 are produced.