Question

PLEASE ANSWER ASAP

A study was conducted comparing the speeds of 2 different fish, Fish A and Fish B. The table shows the distance, in meters, Fish A travels in seconds. Scientists
concluded that Fish B travels 3 meters every 2 seconds.

Assuming both fish swim at a constant rate, which fish swims faster and by how many meters per second?

Answer 1

Fish A travels faster and by 0.1 meters per second.

Explanation:

According to the table, you can see that the seconds are not being measured constantly. To determine the rate of change of meters per second, we can use subtraction on both the numerator and denominator of the expression. Where we divide it into 1 second.

meters/second → 4.8 – 1.6 / 3 – 1 = 3.2 / 2 =

1.6 meters/second.

Now we can compare the rate from fish B by also diving it into 1 second.

3 meters every 2 seconds → 3/2 =

1.5 meters/second.

Since 1.6 > 1.5, Fish A is faster!

And to compare the simplified rates

1.6 – 1.5 = 0.1 meters.

So Fish A is 0.1 meters faster!