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Please help find the variable in both triangles.

Please help find the variable in both triangles.-example-1

2 Answers

4 votes

Explanation:

these are projections from V and W to the same projection "screen" (SU and YX).

since the angles are equal, the ratio between projection beam length and screen length must be the same.

so,

6.

24/14 = 48/x

48/28 = 48/x

x = 28

7.

besides the projection principle, we have a basic triangle situation :

the bisector of the angle W is also bisecting the opposing side YX. that means that this is an isoceles triangle (both legs are equally long).

therefore,

y = 4×sqrt(2)

User ENca
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2 votes

Answer:


\textsf{6.} \quad x = 28


\textsf{7.} \quad y = 4√(2)

Explanation:

What is an angle bisector?

An angle bisector is a line that divides an angle into two equal parts.

Angle Bisector Theorem

An angle bisector in a triangle divides the opposite side into two segments which are in the same proportion as the other two sides of the triangle.

Question 6

Applying the Angle Bisector Theorem:


\implies (UT)/(TS)=(VU)/(VS)


\implies (x)/(14)=(48)/(24)

Cross multiply:


\implies 24 \cdot x=48 \cdot 14


\implies 24x=672

Divide both sides by 24:


\implies (24x)/(24)=(672)/(24)


\implies x=28

Question 7

Applying the Angle Bisector Theorem:


\implies (XZ)/(ZY)=(WX)/(WY)


\implies (4)/(4)=(y)/(4√(2))

Carry out the division on the left side:


\implies 1=(y)/(4√(2))

Multiply both sides by 4√2:


\implies 1\cdot 4√(2)=(y)/(4√(2))\cdot 4√(2)


\implies 4√(2)=y


\implies y=4√(2)

User Badre
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7.0k points