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1 vote
For the below figure, the coordinates of the particles are:

Q1 (-2, 0)
Q2 (2m, 0)
Q3 (0,2m)
01-02-1nC
Determine the charge magnitude for Q3 to ensure the net force on Q3 is facing down the Y axis with a net magnitude of 5.9 Micro N
Q3
D
Y axis
08
x axis

User Ron Thomas
by
8.7k points

1 Answer

4 votes

Answer:

To determine the charge magnitude for Q3, we need to use Coulomb's Law, which states that the force between two point charges is proportional to the product of the charges and inversely proportional to the square of the distance between them.

The net force on Q3 is given as F_net = F_12 + F_13 + F_23

The force between Q1 and Q3 is given as F_13 = (1/(4πε)) * (Q1*Q3)/(D^2)

The force between Q2 and Q3 is given as F_23 = (1/(4πε)) * (Q2*Q3)/((2m-D)^2)

The force between Q1 and Q2 is given as F_12 = (1/(4πε)) * (Q1*Q2)/(2m)^2

where ε is the electric constant and D is the distance between Q3 and Q1 along the Y-axis

By equating the net force to the given value of 5.9 Micro N we can solve for Q3.

Step-by-step explanation:

Above

User Bo Chen
by
7.9k points