Question

PLEASE SHOW WORK…!!!!!!!

Answer 1

see explanation

Explanation:

11

the sum of the 3 angles in a triangle = 180° , then

∠ B + 75° + 90° = 180°

∠ B + 165° = 180° ( subtract 165° from both sides )

∠ B = 15°

12

using the sine ratio in the right triangle

sin75° =
`(opposite)/(hypotenuse)` =
`(BC)/(AB)` =
`(125)/(x)` ( multiply both sides by x )

x × sin75° = 125 ( divide both sides by sin75° )

x =
`(125)/(sin75)` ≈ 129.4 ( to 1 decimal place )

13

using the tangent ratio in the right triangle

tan75° =
`(opposite)/(adjacent)` =
`(BC)/(AC)` =
`(125)/(y)` ( multiply both sides by y )

y × tan75° = 125 ( divide both sides by tan75° )

y =
`(125)/(tan75)` ≈ 33.5 ( to 1 decimal place )