Question

The density of osmium (the densest metal) is 22.57 g/cm3.

What volume would be occupied by 2.77 kg of osmium?

Answer 1

To determine the volume that 2.77 kg of osmium occupies, convert the mass to grams and then divide by the density. The calculation shows that 2.77 kg of osmium would occupy approximately 122.7 cm³ of volume.

Step-by-step explanation:

The question asks what volume would be occupied by 2.77 kg of osmium, given that the density of osmium is 22.57 g/cm3. To find the volume, we can use the formula: volume = mass/density. First, we need to convert the mass from kilograms to grams because the density is given in grams per cubic centimeter (g/cm3).

Therefore, mass = 2.77 kg × 1000 g/kg = 2770 g.

Next, we use the density to find the volume:

Volume = Mass / Density
Volume = 2770 g / 22.57 g/cm3
Volume ≈ 122.7 cm3

So, 2.77 kg of osmium would occupy approximately 122.7 cm3 of volume.

Answer 2

approximately 123.36 cm3.

Step-by-step explanation:

To determine the volume occupied by 2.77 kg of osmium, we can use the density formula:

Density = mass/volume

We know the density and the mass of osmium, so we can rearrange the formula to solve for the volume:

volume = mass/density

We have the mass in kg so we need to convert it to grams

2.77*1000= 2770 g

Now we can substitute the values into the formula:

volume = 2770 g / 22.57 g/cm3 = 123.36 cm3

So, 2.77 kg of osmium would occupy a volume of approximately 123.36 cm3.