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How do I prove ABCD to be a rectangle in algebra 1
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How do I prove ABCD to be a rectangle in algebra 1

User Rick T
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Answer:

Because ABCD is a parallelogram, its opposite sides are equal. (matching angles of congruent triangles). DCB = 90o . Hence ABCD is rectangle, because it is a parallelogram with one right angle.

User BenC
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