In ΔJKL, j= 18 cm, l= 70 cm and ∠L=36°. Find all possible values of ∠J, to the nearest degree

asked Oct 22, 2024 101k views

1 vote

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6 votes

Answer: 9∘

Explanation:

sinA/a = sinB/b

VATSHAL answered Oct 24, 2024

6.8k points

4 votes

This is a straight application of the law of cosine: j2 = k2 + l2 -2 kl cos angle

You make the substitutions and do the arithmetic.

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