Option D is the right option. The maximum height of the ball was 2.5 seconds after it was thrown.
Let b and h be the zeros of the function f(x). If this statement is true, then f(x)= k(x-a)(x-b) would be our equation. Let k be our coefficient.
From the given table,
At t = 0
h(0)= 0
At t = 5
h(5) = 0
So, 0 and 5 are the zeros of the function h(t).
h(t)=k(t-0)(t-5)
h(t)=k(t)(t-5)
Now substitute any point from the table i.e, (2, 96) in [1] to find k.
96=k(2)(2-5)
96=k(2)(-3)
Now, we simplify!
96=-6k
k=-16
Now, we have the equation for h(t)
h(t)=-16(t-5)
h(1)=-16t^2+80t
Initial height of the ball: h(0) = 0 To find the maximum height of the ball, we will use the quadratic equation y=ax^2+bx+c.....[2], the the axis of symmetry is given by: x=-b/2a
Now that we know b= -16 and h= 80 we can perform this equation to find out for t:
t=-80/2(-16)=80/32=2.5 seconds
We can now come to the conclusion that the statement "The maximum height of the ball was reached 2.5 seconds after it was thrown." is the one true statement.
I hope this helps!! o(〃^▽^〃)o