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The arm of a crane at a construction site is

16.0 m long, and it makes an angle of 12.9°
with the horizontal. Assume that the max-
imum load the crane can handle is limited
by the amount of torque the load produces
around the base of the arm.
What maximum torque can the crane with-
stand if the maximum load the crane can
handle is 737 N?
Answer in units of N. m.

1 Answer

2 votes

To solve this problem, we can use the concept of torque. Torque is a measure of the rotational force around an axis, and it is equal to the force applied multiplied by the distance from the axis to the point where the force is applied.

In this case, the crane arm is 16.0 m long, and the angle between the arm and the horizontal is 12.9°. We can use these values to calculate the distance from the axis of rotation to the point where the force is applied. To do this, we can use the trigonometric function sine.

sin(12.9) = opposite side / hypotenuse

distance from the axis = opposite side = (16.0 m) * sin(12.9)

To calculate torque we can use this formula:

torque = force * distance

Given that the maximum load the crane can handle is 737 N, we can substitute this value into the torque equation:

torque = 737 N * distance

maximum torque = 737 N * (16.0 m) * sin(12.9)

The unit of torque is N.m, so the answer will be in N.m

User Nezreli
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