1. What is the weight of a 25.0 kg object near the surface of the earth?

asked Jul 26, 2024 12.6k views

2 votes

by Tzane

7.5k points

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3 votes

Answer:

below

Step-by-step explanation:

F = 'weight' = ma

= 25.0 kg * 9.81 m/s^2 = 245 N

CWSpear answered Aug 1, 2024

8.3k points

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