Explanation:
Using the Identity, sin2θ=2tanθ1+tan2θ, we get,
sin2θ=2⋅4091+(409)2,
=809÷168181.
⇒sin2θ=7201681.
θ∈Q1⇒0<θ<π2⇒0<2θ<π.
∴sin2θ>0.
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