Question

how much heat is absorbed by 0.06 kg of copper when it is heated from 20.0°c to 80.0°c? the specific heat value of copper is 710 j/kg c.

Answer 1

2.556 KJ

Explanation: As we know that:

Q=mcΔT;

where

Q=total heat absorbed by substance

m=mass of the substance

c=specific heat

ΔT=T2-T1;

T2=final temperature

T1= initial temperature

According to our question,

mass of substance(m)=0.06 kg

Specific Heat of copper (c)=710 j/kg°C

initial Temperature(T1)=20°C

final temperature(T2)=80°C

so, temperature difference (ΔT)=T2-T1;

ΔT=(80-20)°C

ΔT=60°C

According to our formula,

Q=mcΔT

=(0.06×710×60) J

=2556 J

=2.556 KJ

Answer 2

Use this formula,

Q= mcθ (m-mass, c- specific heat capacity, θ- temperature change)

Q = mcθ
= 0.06 x 710 x (80-20)
= 0.06 x 710 x 60
= 2556

So the answer is 2556 J