Answer:
To solve for the voltage drop at V₁, we can use Ohm's law, which states that the voltage drop across a resistor (V) is equal to the current (I) flowing through it multiplied by the resistance (R) of the resistor.
V = I * R
The information given in the question is as follows:
VT = 101.00 V
T = Unknown
R₁ = Unknown
V₁= Unknown
I₁=Unknown
R₂= Unknown
V₂= 33.00 V
I₂ = 12.00 Amperes
R₂ = Unknown
V₃ = 37.00 V
I₃ = 13.00 Amperes
R₃ = 12.00 Ohms
The first step is to calculate the current flowing through the circuit by using the formula Power= Voltage * Current
P = VT
I = P/VT = 101/101 = 1 Amperes
Now we can use Ohm's Law to find the voltage drop across R1:
V₁ = I * R₁ = 1 * R₁
To find the resistance of R1, we can use the formula:
T = V₁ + V₂ + V₃
R₁ = (T - V₂ - V₃) / I
Substituting the values,
101 = V₁ + 33 + 37
V₁ = (101 - 33 - 37) = 31 Volts
So, the voltage drop at V₁, which is the voltage drop at resistor one, is 31 Volts.
Step-by-step explanation: