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A 15 Ω resistor has 6 A of current traveling through it. what is the voltage of the battery of the circuit? * work out and use units*

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Answer: The voltage of the battery in the circuit is 90 V.

Explanation: The relationship between current, voltage, and resistance in an electric circuit can be described by Ohm's Law:

V=IR

Where V is the voltage, I is current, and R is the resistance.

We know that the resistance of the resistor is 15 Ω and the current through the resistor is 6 A. To find the voltage of the battery, we can use the formula:

V = IR

V = 15 Ω x 6 A

V = 90 V

Therefore, the voltage of the battery in the circuit is 90 V.

It means that the battery has to have a potential difference of 90V to maintain the current of 6 A flowing through the 15 Ω resistor.

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