Question

the ball of mass 1000g is dropped from a height of 5m and rebounds to a height of 25m calculate the kinetic energy just before impact​

Answer 1

Here's the kinetic energy of the ball before it hits after 25m though.

GravitationalPotentialEnergy=KineticEnergy

GPE=m×g×h=1000kg×9.8m/s2×25m=245,000kg⋅m2/s2

So

Ke=245,000

Joules

To prove it..

v=2gh−−−√=2×9.8×25−−−−−−−−−−√=22.1359m/s

Ke=12mv2=12×1000×22.13592=

245,000J

Step-by-step explanation:

First, a ball cannot be dropped from 5m and then bounce to 25m without some sort of external energy source.

Second, I'm not sure if you're asking for the kinetic energy before it hits the ground the first time, or before it hits the ground after 25m.

Third, if you're asking for the first bounce, I don't believe it can be calculated. We would need to know more about the collision like the elasticity of the ball.