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The equation of the line that passes through (2, - 6) and is perpendicular to y = 2/3 x + 4

1 Answer

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Answer:

y = -3/2 x -3

Explanation:

Perpendicular slopes are the opposite reciprocals.

The new slope will be -3/2

m = -3/2

x = 2 Given in the point (2,-6)

y = -6 Given in the point (2,-6)

Substitute these in to y = mx + b and solve for b

-6 = (-3/2)(2) + b

-6 = -3 + b Add 3 to both sides

-6 + 3 = -3 + 3 + b

-3 = b

We know have the m (-3/2) and the b (-3) to write the equation

y = mx + b

y = -3/2 x -3

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