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Find the dimensions of a rectangle whose width is 6 miles less than its length, and whose area is 72 square miles.

1 Answer

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Answer:

Dimensions are 12 , 6

Explanation:

Forming algebraic equations and solving:

Let the length be 'x' miles.

width = (x - 6) miles

Area of a rectangle = length * width

x *(x -6) = 72 square miles

x*x - x *6 = 72

x² - 6x -72 = 0

Sum = -6

Product = -72

Factors = -12 , 6 { -12 * 6 = -72 & -12 + 6 = -6}

x² - 12x + 6x - 72 = 0 {Rewrite the middle term using the factors}

x(x - 12) +6(x - 12)=0

(x -12)(x + 6) =0

x - 12 = 0 ;

x = 12

{x + 6= 0 is ignored, as dimensions will not have negative value}

length = 12 miles

widht = 12 - 6 = 6 miles

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