Question

An object is dropped from 28 feet below the tip of the pinnacle atop a 928-ft tall building. The height h the object after t seconds is given by the equation h=-16t^(2)+900. Find how many seconds pass before the object reaches the ground.

Answer 1

Answer: it takes 7.5 seconds for the object to reach the ground.

Step-by-step explanation:

The equation for the height of the object is h=-16t^2+900. To find the time when the object reaches the ground, we need to find the value of t when h=0.

Therefore, we can set h=-16t^2+900 = 0 and solve for t:

-16t^2+900 = 0

-16t^2 = -900

t^2 = 56.25

t = sqrt(56.25)

t = 7.5

So, it takes 7.5 seconds for the object to reach the ground.